5x^2-28x-153=0

Solution for 5x^2-28x-153=0 equation:

5x^2-28x-153=0

a = 5; b = -28; c = -153;
Δ = b2-4ac
Δ = -282-4·5·(-153)
Δ = 3844
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{3844}=62$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-28)-62}{2*5}=\frac{-34}{10}
=-3+2/5
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-28)+62}{2*5}=\frac{90}{10}
=9
$